0=8x^2-29x+15

Solution for 0=8x^2-29x+15 equation:

0=8x^2-29x+15

We move all terms to the left:

0-(8x^2-29x+15)=0

We add all the numbers together, and all the variables

-(8x^2-29x+15)=0

We get rid of parentheses

-8x^2+29x-15=0

a = -8; b = 29; c = -15;
Δ = b2-4ac
Δ = 292-4·(-8)·(-15)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-19}{2*-8}=\frac{-48}{-16}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+19}{2*-8}=\frac{-10}{-16}
=5/8
$